B brcinca New member Joined Jan 26, 2007 Messages 3 Jan 26, 2007 #1 I do not know why these 2 problems are an obstacle but I could use the help. Thanks, BRC #1. Solve for x 1000=1102.5/(1+x)^2 #2. Solve for x 1/4=(x-3)^2
I do not know why these 2 problems are an obstacle but I could use the help. Thanks, BRC #1. Solve for x 1000=1102.5/(1+x)^2 #2. Solve for x 1/4=(x-3)^2
D Denis Senior Member Joined Feb 17, 2004 Messages 1,706 Jan 26, 2007 #2 > 1000=1102.5/(1+x)^2 1102.5 / (x^2 + 2x +1) = 1000 ; ok? 1000(x^2 + 2x +1) = 1102.5 ; still with me? x^2 + 2x +1 = 1102.5 / 1000 x^2 + 2x +1 = 1.1025 : wrap it up! > 1/4=(x-3)^2 x^2 - 6x + 9 = 1/4 4x^2 - 24x + 36 = 1 All yours...if you're still lost, means you need a talk with your teacher.
> 1000=1102.5/(1+x)^2 1102.5 / (x^2 + 2x +1) = 1000 ; ok? 1000(x^2 + 2x +1) = 1102.5 ; still with me? x^2 + 2x +1 = 1102.5 / 1000 x^2 + 2x +1 = 1.1025 : wrap it up! > 1/4=(x-3)^2 x^2 - 6x + 9 = 1/4 4x^2 - 24x + 36 = 1 All yours...if you're still lost, means you need a talk with your teacher.
B brcinca New member Joined Jan 26, 2007 Messages 3 Jan 26, 2007 #3 Thanks for the reply Denis. I got everything you wrote but what about solving for the value of x?
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,337 Jan 26, 2007 #4 That would be the "all yours" part. Let's see what you can do.
B brcinca New member Joined Jan 26, 2007 Messages 3 Jan 27, 2007 #5 Got it! I had a total lapse in memory. I ended up using the quadratic equation. Thanks for the push.
D Denis Senior Member Joined Feb 17, 2004 Messages 1,706 Jan 27, 2007 #6 brcinca said: Got it! I had a total lapse in memory. Click to expand... ...I have a good memory, but it's short...
brcinca said: Got it! I had a total lapse in memory. Click to expand... ...I have a good memory, but it's short...