need help with a prob

[forestgirl]

Please help with this if you would. I'm stuck.

9/x + 2 = 2x/x+3

I can show my math if you like.

 

[evinda]

Please help with this if you would. I'm stuck.

9/x + 2 = 2x/x+3

I can show my math if you like.

It is like that: \(\displaystyle \frac{9}{x+2}=\frac{2x}{x+3} \Rightarrow 9(x+3)=2x(x+2) \). Can you continue?

 

[lookagain]

Please help with this if you would. I'm stuck.

9/x + 2 = 2x/x+3

I can show my math if you like.

forestgirl,

did you mean \(\displaystyle \ \ \)(9/x) + 2 = 2x/(x + 3)?


Yes, please show the work you have done up to this point.

 

[forestgirl]

continued

Yes, I meant (9/x) + 2 = 2x/(x + 3)

So far, I have:

x(x+3) multiplied by 9/x + x(x+3) multiplied by 2/1 = x(x+3) multipled by (2x)/(x+3)

 

[lookagain]

ok.
9/x + 2 = 2x/x+3

x(x+3) . 9/x + x(x+3) . 2/1 = x(x+3) . 2x/x+3

When you are meaning \(\displaystyle \dfrac{2x}{x + 3}, \ \) and you write it horizontally, you must put the denominator in

grouping symbols, such as 2x/(x + 3), because what you wrote means 2x/x + 3. That isn't what you intend.

Also, I wouldn't use the dot for multiplication when writing it out horizontally. You may want to use an

asterisk, set of parentheses, square brackets, or braces instead for the multiplication.


Cancel out appropriate factors below, thus eliminating all of the fractions. \(\displaystyle \\ \ \) <------ edit
I'm going to leave all of the rest of the steps to you.


\(\displaystyle \dfrac{x(x + 3)}{1}\cdot\dfrac{9}{x} \ + \ \dfrac{x(x + 3)}{1}\cdot\dfrac{2}{1} \ = \ \dfrac{x(x + 3)}{1}\cdot\dfrac{2x}{x + 3}\)