K kluda06 New member Joined Apr 28, 2013 Messages 12 Sep 18, 2013 #1 i have to evaluate the integral using U*V-∫V*DU ∫sin-12xdx i just do not know if i am getting my du right. I did: u=sin-12x du= 2/ square root of (1-(2x)2) ???? dv=dx v=x Please let me know if i am correct on this so far.
i have to evaluate the integral using U*V-∫V*DU ∫sin-12xdx i just do not know if i am getting my du right. I did: u=sin-12x du= 2/ square root of (1-(2x)2) ???? dv=dx v=x Please let me know if i am correct on this so far.
D daon2 Full Member Joined Aug 17, 2011 Messages 999 Sep 19, 2013 #2 yes, but you missed a dx. should be a simple substitution now
