need help with solving (5x^2 y^5)^2(3x^3 y^4)^3

[siki08]

(5x^2 y^5)^2(3x^3 y^4)^3

the answer choices are:
a. 675x^13 y^22
b. 675x^36 y^120
c. 15x^36 y^120
d. 15x^13 y^22
e. 15x^7 y^14

 

[Deleted member 4993]

Re: need help with solving (5x^2 y^5)^2(3x^3 y^4)3

(5x^2 y^5)^2(3x^3 y^4)^3

the answer choices are:
a. 675x^13 y^22
b. 675x^36 y^120
c. 15x^36 y^120
d. 15x^13 y^22
e. 15x^7 y^14

Hint:

Use

[a^m] * [a^n] = a^(m+n)

and

[a^m]^n = a^(m*n)

Now show your work and tell us exactly where you are stuck.

 

[siki08]

i'm stuck.
i honestly don't have a clue
to what i'm doing. period.

 

[Denis]

If you don't have a clue what you're doing, then WHY were you given this?

As example, if you don't know/understand that (3^4)^7 = 3^28
or 3^4 times 3^7 = 3^11, then you're sure not ready for this problem...

 

[siki08]

i get that much.

but i think i have an idea of what to do.

I should start by using the FOIL method I guess.
But, do I multiply or add the exponents?

 

[Denis]

Start this way:
(5x^2 y^5)^2
(5x^2)^2 = 25x^4
(y^5)^2 = y^10
so that now is: (25x^4)(y^10)

go do the other one similarly;
then do the multiplications.

 

[stapel]

need help with solving...

i honestly don't have a clue to what i'm doing. period.

i think i have an idea of what to do.
I should start by using the FOIL method I guess.
But, do I multiply or add the exponents?

There is no actual FOILing or solving to do here. (There is no binomial to expand, and there is no equation to solve.)

It sounds as though you are not familiar with the rules for exponents. It is unfortunate that this material was assigned before having been covered in class. :shock:

Since we cannot reasonably provide the requested lessons within this environment, please use some online lessons instead. :idea:

. . . . .Gooogle results for "exponents"

. . . . .Gooogle results for "simplifying exponents"

Once you have studied a few lessons and have learned the basic terms and techniques, please attempt this exercise. If you get stuck, please show all of your work and reasoning. Thank you!

Eliz.