Need help with some limits
- Thread starter wewfy
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D
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Is it:
\(\displaystyle \lim_{n \to \infty}\)
or
\(\displaystyle \lim_{n \to 0}\)
or something else?
HallsofIvy
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- Jan 27, 2012
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Since n is typically used to represent an integer I would be inclined to assume that the limit is as n goes to infinity.
My first thought was to get rid of the 5th root.
\(\displaystyle (a- b)(a^4+ a^3b+ a^2b^2+ ab^3+ b^4)= a^5- b^5\)
Here, \(\displaystyle a= \sqrt[5]{n^5- n^4+ 1}\) and \(\displaystyle b= n\).
My first thought was to get rid of the 5th root.
\(\displaystyle (a- b)(a^4+ a^3b+ a^2b^2+ ab^3+ b^4)= a^5- b^5\)
Here, \(\displaystyle a= \sqrt[5]{n^5- n^4+ 1}\) and \(\displaystyle b= n\).