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[ramius27]

Using the laws of indices, find the exact value of 6^x given that 3^x+4 = 12^4-x

 

[Deleted member 4993]

Using the laws of indices, find the exact value of 6^x given that 3^x+4 = 12^4-x

Is the given condition:

\(\displaystyle 3^x + 4 = 12^4 - x\) ...................................... as posted, or

\(\displaystyle 3^{x + 4} = 12^{4 - x}\) .............................should be posted as 3^(x+4) = 12^(4-x).... those parentheses are super important, or

something else.

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:

https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520​

Please share your work/thoughts about this problem.

 

[Steven G]

Is the given condition:

\(\displaystyle 3^x + 4 = 12^4 - x\) ...................................... as posted, or

\(\displaystyle 3^{x + 4} = 12^{4 - x}\) .............................should be posted as 3^(x+4) = 12^(4-x).... those parentheses are super important, or

something else.

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:

https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520​

Please share your work/thoughts about this problem.

How do you scare away a student with such a nice reply?

 

[Dr.Peterson]

Using the laws of indices, find the exact value of 6^x given that 3^x+4 = 12^4-x

Assuming you meant 3^(x+4) = 12^(4-x), start by rewriting it as 3^x 3^4 = 12^4 12^-x. Then try to collect all terms with x on one side.