Three workers sort 66 boxes in a day. One of the workers(B1) is three times more productive than the second worker (B2) and twice as productive as the third worker(B3). How many boxes did the second most productive worker sort?
A. 24
B. 18
C. 10
D. 15
E. 20
There are three worker - we do not know which one is the most productive - yet. So
Number of boxes the first worker sort = B1
Number of boxes the second worker sort = B2
Number of boxes the third worker sort = B3
Three workers sort 66 boxes in a day → B1 + B2 + B3 = 66......................................................... (1)
One of the workers(B1) is three times more productive than the second worker (B2) → B1 = 3 * B2 → B2 = B1/3 ..................... (2)
One of the workers(B1) is twice as productive as the third worker(B3) → B1 = 2 * B3 → B3 = B1/2 ..................... (3)
Replacing B2 and B# from (2) and (3) into (1), we get:
B1 + B1/3 + B1/2 = 66 → B1 = ?? ....................................................................................(4)
Replace B1 from (4) into (2) and (3) and solve for B2 and B3
Now decide who is the second most productive worker, and finish answering the question......