L lake New member Joined Nov 16, 2007 Messages 5 Nov 16, 2007 #1 Find two consecutive numbers such that the difference of their reciprocals is 1/4 the reciprocal of the small number.
Find two consecutive numbers such that the difference of their reciprocals is 1/4 the reciprocal of the small number.
S scrum Junior Member Joined Oct 11, 2007 Messages 55 Nov 16, 2007 #2 Find two consecutive numbers such that the difference of their reciprocals is 1/4 the reciprocal of the small number. I would write that as abs((1/x) - (1/x+1)) = (1/4)(1/x) but I may be wrong.
Find two consecutive numbers such that the difference of their reciprocals is 1/4 the reciprocal of the small number. I would write that as abs((1/x) - (1/x+1)) = (1/4)(1/x) but I may be wrong.
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Nov 16, 2007 #3 scrum said: I would write that as abs((1/x) - (1/x+1)) = (1/4)(1/x) Click to expand... Since x + 1 is larger than x, then 1/(x + 1) is smaller than 1/x, and the absolute-value bars are not necessary. Otherwise, your set-up is fine. Eliz.
scrum said: I would write that as abs((1/x) - (1/x+1)) = (1/4)(1/x) Click to expand... Since x + 1 is larger than x, then 1/(x + 1) is smaller than 1/x, and the absolute-value bars are not necessary. Otherwise, your set-up is fine. Eliz.
