M minhajoooo New member Joined Mar 29, 2023 Messages 1 Mar 29, 2023 #1 This is a little beginner level, but how do we normalize Ψ= x(a-x). I do not understand how separate the a from the equation.
This is a little beginner level, but how do we normalize Ψ= x(a-x). I do not understand how separate the a from the equation.
topsquark Senior Member Joined Aug 27, 2012 Messages 2,363 Mar 29, 2023 #2 minhajoooo said: This is a little beginner level, but how do we normalize Ψ= x(a-x). I do not understand how separate the a from the equation. Click to expand... In general, set $\psi (x) = A ( x( a - x) )$ Then $1 = \int_a^b \psi ^*(x) \psi (x) \, dx$ (In general A can be complex, but usually we can make it real.) You can do this and keep the a. The only way to get rid of that is if you have a boundary condition you need to fill, and you didn't give one. -Dan
minhajoooo said: This is a little beginner level, but how do we normalize Ψ= x(a-x). I do not understand how separate the a from the equation. Click to expand... In general, set $\psi (x) = A ( x( a - x) )$ Then $1 = \int_a^b \psi ^*(x) \psi (x) \, dx$ (In general A can be complex, but usually we can make it real.) You can do this and keep the a. The only way to get rid of that is if you have a boundary condition you need to fill, and you didn't give one. -Dan