not sure how to plug this answer in to see if correct

[sarahj3]

Solve: 1/8x^2+1/5x=-30/40

40*1/5x^2=3*40/40
5x^2+8x=-3
-8+or- the square root of 64-4*5*3/2*5
-8+or-8 the square root of 4/10
-8+or- 2/10=-6/10 x1=-3/5
x2=-10/10 =-1

 

[jsbeckton]

if you have x^2=-10/10
which means x=the square root of a negative number.
have you talked agout "i", imaginary numbers?

and to "plug in" to check your anwser, just put a -1 everywhere you have an x

 

[jsbeckton]

Solve: 1/8x^2+1/5x=-30/40

40*1/5x^2=3*40/40

Why are you multiplying 1/5x^2 by 40?
You don't even have a 1/5x^2 in your equation

1/8x^2+1/5x=-30/40

If you want to reduce you have to multiply EACH term by 40.