On a certain street there are 31 houses. | Math HELP! URGENT!

Vanguard

New member
Joined
Oct 10, 2017
Messages
1
On a certain street, there are 31 houses. 12 of those houses have fewer than 7 rooms. 10 of those houses have more than 8 rooms. 8 of those houses have more than 9 rooms. What is the total number of houses that have 7, 8, or 9 rooms? Explain.

Very Urgent! Please reply below!!!
 
On a certain street, there are 31 houses. 12 of those houses have fewer than 7 rooms. 10 of those houses have more than 8 rooms. 8 of those houses have more than 9 rooms. What is the total number of houses that have 7, 8, or 9 rooms? Explain.
What are your thoughts? What have you tried? How far have you gotten? Where are you stuck?

For instance, you used the fact that ten houses had 9 or more rooms ("more than 8"), along with the fact that eight of the houses had 10 or more rooms, and concluded... what? (Hint: How many houses must have exactly 9 rooms?)

When you reply, please include any other information for this exercise (I think something is missing, unless they're just wanting a total), along with a clear listing of your thoughts and efforts so far. (Also, are you allowed to get outside help on this quiz?) Thank you! ;)
 
There are "10 houses with more than 8 rooms" and "8 houses with more than 9 rooms". So how many houses have exactly 9 rooms?

There are "12 houses that have fewer than 7 rooms" so there must be 31- 10- 12= 9 houses that have either 7 or 8 rooms but I see no way to tell exactly how many had 7 rooms and how many had 8 rooms. Is it possible that one of "fewer" or "more" included "or equal to"?
 
Last edited:
Top