g(x)=x2-9 & h(x)=radical 3x+12 what is the function or how do i find it
L lynnholman New member Joined Apr 19, 2007 Messages 2 Apr 19, 2007 #1 g(x)=x2-9 & h(x)=radical 3x+12 what is the function or how do i find it
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Apr 19, 2007 #2 Re: one more \(\displaystyle \L\\g(x)=x^{2}-9 \;\ & \;\ h(x)=\sqrt{3x+12}\) what is the function or how do i find it Click to expand... We don't know if you don't. What are you expected to do?. Composition function perhaps?. Maybe g(h(x))?. Something like that?. If it is a composition, i.e. g(h(x)), then insert h(x) into g(x) like so: \(\displaystyle \L\\(\sqrt{3x+12})^{2}-9=3x+12-9=3(x+1)\) See how that works?. I subed h(x) in for x in g(x).
Re: one more \(\displaystyle \L\\g(x)=x^{2}-9 \;\ & \;\ h(x)=\sqrt{3x+12}\) what is the function or how do i find it Click to expand... We don't know if you don't. What are you expected to do?. Composition function perhaps?. Maybe g(h(x))?. Something like that?. If it is a composition, i.e. g(h(x)), then insert h(x) into g(x) like so: \(\displaystyle \L\\(\sqrt{3x+12})^{2}-9=3x+12-9=3(x+1)\) See how that works?. I subed h(x) in for x in g(x).