Given 5 different green dyes, four different blue dyes and three different red dyes, how many combinations of dyes can be chosen taking at least one green and one blue dye?
I approached the sum like this :
I already picked one green and one blue .
There are nine total green blue dyes.
Choosing two out of 9 --> 5c1*4c1
After choosing two dyes one from green and one blue.
So now I have 10 dyes.
Each have a option of yes or no .
So, 2^10 =1024
1024* 5c1*4c1= ....
As far as I broke down some combination ,
G1B1 can happen
G1B1 G2 B2
G1 B1 r1 all blue dyes ...
Don't give alternate solution
Where am I wrong.
I approached the sum like this :
I already picked one green and one blue .
There are nine total green blue dyes.
Choosing two out of 9 --> 5c1*4c1
After choosing two dyes one from green and one blue.
So now I have 10 dyes.
Each have a option of yes or no .
So, 2^10 =1024
1024* 5c1*4c1= ....
As far as I broke down some combination ,
G1B1 can happen
G1B1 G2 B2
G1 B1 r1 all blue dyes ...
Don't give alternate solution
Where am I wrong.
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