parallelogram problem: ABCD-parallelogram, AB is perpendicular to BD, the total perimeter equals 32 cm, BD=8 cm; find area

[ouch8y]

the problem goes like this: ABCD-parallelogram, AB is perpendicular to BD, the total perimeter equals 32 cm, BD=8 cm. I need to find the total area of the parallelogram. I halved the perimeter to find the perimeter of each triangle formed as shown in the image below. I then used a system of two equations to find AD : AB^2 + 64=AD^2 and AD+AB+8=16. Turns out that AD equals 0. Please help,

 

[The Highlander]

the problem goes like this: ABCD-parallelogram, AB is perpendicular to BD, the total perimeter equals 32 cm, BD=8 cm. I need to find the total area of the parallelogram. I halved the perimeter to find the perimeter of each triangle formed as shown in the image below. I then used a system of two equations to find AD : AB^2 + 64=AD^2 and AD+AB+8=16. Turns out that AD equals 0. Please help,

Hi @ouch8y,

Please post you pictures the right way up!

Your second equation ("AD+AB+8=16") is wrong....
See adjusted pic (below)

Have another go and show us your new results, please.

Hope that helps.

​