parameter

[red and white kop!]

im supposed to eliminate A from the pair of equations
x= sin2A
y= sec4A

ive learnt most trig identities i think, up to the double angle identities etc.
ive done several problems like this but here im stuck

 

[Deleted member 4993]

im supposed to eliminate A from the pair of equations
x= sin2A
y= sec4A

ive learnt most trig identities i think, up to the double angle identities etc.
ive done several problems like this but here im stuck

Is it

x = sin(2A)
y = sec(4A)

If it is - then you should write those with parentheses.

or is it

x = sin[sup:1mud81to]2[/sup:1mud81to](A)
y = sec[sup:1mud81to]4[/sup:1mud81to](A)

or is it

x = sin(2) * A
y = sec(4) * A

Or something else.....

 

[red and white kop!]

it is sin(2A) and sec(4A) obviously enough i think! why would it be to the powers?
can somebody actually help me please?

 

[Denis]

im supposed to eliminate A from the pair of equations
x= sin2A
y= sec4A

You could always use an eraser :idea:
I did; worked fine:
x= sin2
y= sec4

 

[Deleted member 4993]

it is sin(2A) and sec(4A) obviously enough i think! why would it be to the powers?
can somebody actually help me please?

why would it be to the powers? -- That is a ridiculous question!!

Anyway - can you express Cos(2A) in terms of Sin(A) - or Cos(4A) in terms of Sin(2A)? - and finally Sec(4A) in terms of Cos (4A) - isn't that obvious!!!

 

[mmm4444bot]

it is sin(2A) and sec(4A) obviously enough i think!

What is obvious enough to me is that you do not understand function notation.

Perhaps, you don't even know that sine is a function.