F FizzyCrow New member Joined Nov 12, 2004 Messages 5 Oct 27, 2005 #1 I have a question here that is bugging me!! Thanks for any info Find the parametric equations for the line tangent to the helix r=(sqr2 cos(t))i+(sqr2 sin(t)j+tk at the point where t=pi/4.
I have a question here that is bugging me!! Thanks for any info Find the parametric equations for the line tangent to the helix r=(sqr2 cos(t))i+(sqr2 sin(t)j+tk at the point where t=pi/4.
S soroban Elite Member Joined Jan 28, 2005 Messages 5,584 Oct 27, 2005 #2 Hello, FizzyCrow! Find the parametric equations for the line tangent to the helix r = (√2·cos(t))i + (√2·sin(t)j + tk at the point where t = π/4. Click to expand... When t = π/4, the point is: . [√2·cos(π/4)]i + [√2·sin(π/4)j + (π/4)k .= .(1, 1, π/4) The derivative is: .r' .= .[-√2·sin(t)]i + [√2·cos(t)]j + k . . When t = π/4: .r' .= .[-√2·sin(π/4)]i + [√2·cos(π/4)]j + k .= .[-1, 1, 1] The parametric equations are: .x .= .1 - t, . y .= .1 + t, . z .= .π/4 + t
Hello, FizzyCrow! Find the parametric equations for the line tangent to the helix r = (√2·cos(t))i + (√2·sin(t)j + tk at the point where t = π/4. Click to expand... When t = π/4, the point is: . [√2·cos(π/4)]i + [√2·sin(π/4)j + (π/4)k .= .(1, 1, π/4) The derivative is: .r' .= .[-√2·sin(t)]i + [√2·cos(t)]j + k . . When t = π/4: .r' .= .[-√2·sin(π/4)]i + [√2·cos(π/4)]j + k .= .[-1, 1, 1] The parametric equations are: .x .= .1 - t, . y .= .1 + t, . z .= .π/4 + t
