I have to write out the decomposition and find the numerical values of A, B, C, etc.
Problem:
x^2+9x-12
(3x-1)(x+6)^2
My work so far:
A/(3x-1) + B/(x+6) + C/(x+6)^2
x^2+9x-12 = A(x+6)^2 + B(3x-1)(x+6) + C(3x-1)
And so I solved for A, B, and C but got really weird fractions like 147/361.
If you could help out here that would be great! Thanks!
Problem:
x^2+9x-12
(3x-1)(x+6)^2
My work so far:
A/(3x-1) + B/(x+6) + C/(x+6)^2
x^2+9x-12 = A(x+6)^2 + B(3x-1)(x+6) + C(3x-1)
And so I solved for A, B, and C but got really weird fractions like 147/361.
If you could help out here that would be great! Thanks!