peak current

[logistic_guy]

Calculate the peak current in $\displaystyle 1.8$-$\displaystyle \text{k}\Omega$ resistor connected to a $\displaystyle 120$-$\displaystyle \text{V} \ \text{rms}$ ac source.

 

[khansaheb]

Calculate the peak current in $\displaystyle 1.8$-$\displaystyle \text{k}\Omega$ resistor connected to a $\displaystyle 120$-$\displaystyle \text{V} \ \text{rms}$ ac source.

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[logistic_guy]

Calculate the peak current in $\displaystyle 1.8$-$\displaystyle \text{k}\Omega$ resistor connected to a $\displaystyle 120$-$\displaystyle \text{V} \ \text{rms}$ ac source.

Another beautiful relation between $\displaystyle V_{\text{rms}}$ and $\displaystyle V_0$ is:

$\displaystyle V_{\text{rms}} = \frac{V_0}{\sqrt{2}} = \frac{I_0R}{\sqrt{2}}$

Solving for the peak current gives:

$\displaystyle I_0 = \frac{\sqrt{2}V_{\text{rms}}}{R} = \frac{\sqrt{2}(120)}{1800} = \textcolor{blue}{94.3 \ \text{mA}}$