Perform the calculation: 90° - 74° 57' 15"

awpd229

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Perform the calculation: 90° - 74° 57' 15"

Perform the calculation:

90° - 74° 57' 15"
 
This is just a simple subtraction. Note that one degree is sixty minutes, and one minute is sixty seconds. Then "borrow" as necessary, and subtract. For instance:

. . .45° 3' - 13° 12' 5"

. . . . .= 44° 63' - 13° 12' 5"

. . . . .= 44° 62' 60" - 13° 12' 5"

. . . . .= (44 - 13)° (62 - 12)' (60 - 5)"

. . . . .= 31° 50' 55"

Where are you stuck? Please be specific. Thank you.

Eliz.
 
awpd229 said:
i dont understand how you got the 44 degrees and 63'
How many minutes are in one degree?

Split "45 degrees" into "44 degrees and" that number of minutes. (That's the "borrowing" mentioned previously.) There already were three minutes. So how many minutes are there now, total, in addition to the 44 degrees?

Eliz.
 
awpd229 said:
No, there are not 47 minutes in one degree.

One circle (one revolution) contains 360 degrees.

One degree contains 60 minutes.

One minute contains 60 seconds.

If you split 45 degrees into 44 degrees plus one degree, then this is equal to 44 degrees plus how many minutes? (Hint: One degree equals sixty minutes.)

Eliz.

Were angle measurements not covered in class...?
 
Re: Perform the calculation: 90° - 74° 57' 15"

awpd229 said:
Perform the calculation:
90° - 74° 57' 15"
Quit guessing!

Bring the 74° 57' 15" up to 75 degrees: what do you need?
Same as clock: 11:57:15 ; how long before 12:00:00 ?
 
90<sup>o</sup> = 89<sup>o</sup> 59' 60"

89<sup>o</sup> 59' 60" - 74<sup>o</sup> 57' 15" = 15<sup>o</sup> 2' 45"
 
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