Perimeter and Area

AdrienneNArndt

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How do you find the smallest possible area of a rectangle with the perimeter being 16 cm, and sides that are whole numbers? What is the greatest possible area?
 
AdrienneNArndt said:
How do you find the smallest possible area of a rectangle with the perimeter being 16 cm, and sides that are whole numbers? What is the greatest possible area?
1 x 7 will give you the minimum area with given constraints (assuming 0 is not allowed).
 
Can you use calculus?


lw = Area
2l + 2w = 16

sub in l for w

-l^2 + 8l = A

dA/Dl = -2l + 8 = 0 at a max or min. l = 4 for the max. but I am not sure how to get the min. in this case
 
AdrienneNArndt said:
How do you find the smallest possible area of a rectangle with the perimeter being 16 cm, and sides that are whole numbers? What is the greatest possible area?

The smallest possible area derives from the rectangle of sides 1 and [16 - (2)1] = 7.

For a given perimeter, the square will result in the maximum area.
Given a square of X by X whose area is X^2.
Reducing one side by "a" and increasing the other side by "a", maintaining the perimeter constant, yields an area of (X - a)(X + a) = X^2 - a^2.
Thus, for a given perimeter, the square encloses the largest area.
 
If question is: find maximum area of a non-square rectangle with integer sides if perimeter = 4k + 2,
then area = k(k + 1)

Example: perimeter = 22
Then 4k + 2 = 22 : k = 5
Area = k(k + 1) = 5(6) = 30

In other words: closest possible to a square.
 
if two tiangles are simimar.the sides of the first one are 13,18 and 20.the smallest sides of the second tiangle is 22.find the perimerters of the second traingle.
 
Two polygons are similar. If the ratio perimeters is 4:7,what is the ratio of the corresponding sides?
 
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