Hello there! I have this wonderful slide with some calculations I'd like to get a grasp on.
Am I right in my interpretation:
1.) Steady state means that the concentration c is 0. What could that mean? I only know that at steady state the change in c would be zero but not the c itself??
2.) then in one-dim:
a) concentration is a function of z, which is the height above the bottom. (and could someone explain the nabla thing please? What does it mean that nabla (->2) times Diffusion times concentration is 0?)
b) then you take the second derivative of the equation (depicted above), which is the same as integrating twice? where the first drivative is a constant (is this a rule that the first integration of 0 is a constant? - or of a constant is a constant?) and the second derivative and
in the second integration you multiply the A1 with z, because that's how you integrate (is there a explanation maybe?
) and add another constant. why can you just like that add another A? Is it an integration rule?
And lastly... with red "ensquared" formula, what could a possible test question look like in this... what would be given by the teacher (and how would you calculate this?) Thanks a lot!
I guess I get the rest.
Am I right in my interpretation:
1.) Steady state means that the concentration c is 0. What could that mean? I only know that at steady state the change in c would be zero but not the c itself??
2.) then in one-dim:
a) concentration is a function of z, which is the height above the bottom. (and could someone explain the nabla thing please? What does it mean that nabla (->2) times Diffusion times concentration is 0?)
b) then you take the second derivative of the equation (depicted above), which is the same as integrating twice? where the first drivative is a constant (is this a rule that the first integration of 0 is a constant? - or of a constant is a constant?) and the second derivative and
in the second integration you multiply the A1 with z, because that's how you integrate (is there a explanation maybe?
) and add another constant. why can you just like that add another A? Is it an integration rule?And lastly... with red "ensquared" formula, what could a possible test question look like in this... what would be given by the teacher (and how would you calculate this?) Thanks a lot!
I guess I get the rest.