PLEASE HELP ME!!!!.... easy calculus
- Thread starter goodnosh7
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pka
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The maximum occurs if the derivative is zero.
\(\displaystyle - \left( {4\cos (\Theta ) - 3\sin (\Theta )} \right) = 0\; \Rightarrow \;\Theta = \arctan \left( {\frac{4}{3}} \right) \vee \arctan \left( {\frac{4}{3}} \right) + 180^ \circ\).
Now you must solve this for k.
\(\displaystyle \frac{1}{{4\sin (\Theta ) + 3\cos (\Theta ) + k}} = 2\)
I get two answers.
\(\displaystyle - \left( {4\cos (\Theta ) - 3\sin (\Theta )} \right) = 0\; \Rightarrow \;\Theta = \arctan \left( {\frac{4}{3}} \right) \vee \arctan \left( {\frac{4}{3}} \right) + 180^ \circ\).
Now you must solve this for k.
\(\displaystyle \frac{1}{{4\sin (\Theta ) + 3\cos (\Theta ) + k}} = 2\)
I get two answers.