please help me: find limit of h(x)=sinx+cosx/sinx−2cosx as x→π/2

[allos]

find the limit of

h(x)=sinx+cosx/sinx−2cosx​

​

as

[FONT=MathJax_Math-italic]x​

[FONT=MathJax_Main]→[/FONT][FONT=MathJax_Math-italic]π/[/FONT][FONT=MathJax_Main]2[/FONT]​

[/FONT]​

 

[pka]

1. find the limit of

[FONT=MathJax_Math-italic]h​

[FONT=MathJax_Main]([/FONT][FONT=MathJax_Math-italic]x[/FONT][FONT=MathJax_Main])[/FONT][FONT=MathJax_Main]=[/FONT][FONT=MathJax_Math-italic]s[/FONT][FONT=MathJax_Math-italic]i[/FONT][FONT=MathJax_Math-italic]n[/FONT][FONT=MathJax_Math-italic]x[/FONT][FONT=MathJax_Main]+[/FONT][FONT=MathJax_Math-italic]c[/FONT][FONT=MathJax_Math-italic]o[/FONT][FONT=MathJax_Math-italic]s[/FONT][FONT=MathJax_Math-italic]x[/FONT][FONT=MathJax_Math-italic]s[/FONT][FONT=MathJax_Math-italic]i[/FONT][FONT=MathJax_Math-italic]n[/FONT][FONT=MathJax_Math-italic]x[/FONT][FONT=MathJax_Main]−[/FONT][FONT=MathJax_Main]2[/FONT][FONT=MathJax_Math-italic]c[/FONT][FONT=MathJax_Math-italic]o[/FONT][FONT=MathJax_Math-italic]s[/FONT][FONT=MathJax_Math-italic]x[/FONT]
​

as

[FONT=MathJax_Math-italic]x[/FONT][FONT=MathJax_Main]→[/FONT][FONT=MathJax_Math-italic]π[/FONT][FONT=MathJax_Main]2[/FONT]​

[/FONT]

If it is \(\displaystyle x\to\pi^2\) then in the future please make it clear: x->pi^2. LOOK AT THIS
If it is not that, then what is it?

 

[stapel]

find the limit of
h(x)=sinx+cosx/sinx−2cosx
as x [FONT=MathJax_Main]→[/FONT][FONT=MathJax_Math-italic]π/[/FONT][FONT=MathJax_Main]2[/FONT]

Okay, now you've changed the equation to be as follows:

. . . . .\(\displaystyle \mbox{Find the limit: }\, \)\(\displaystyle \displaystyle \lim_{x\, \rightarrow\, \frac{\pi}{2}}\,\)\(\displaystyle \bigg(\, \sin(x)\, +\, \dfrac{\cos(x)}{\sin(x)}\, -\, 2\cos(x)\, \bigg)\)

Was this what you meant? Thank you!

 

[Deleted member 4993]

find the limit of

h(x)=sinx+cosx/sinx−2cosx​

​

as

[FONT=MathJax_Math-italic]x​

[FONT=MathJax_Main]→[/FONT][FONT=MathJax_Math-italic]π/[/FONT][FONT=MathJax_Main]2[/FONT]​

[/FONT]​

Just replace 'x' by 'π/2' in h(x) .

Where are you having trouble??

 

[allos]

check my attempts

 

[doubt]

a really easy problem just replace and then it is 1