Please help me!! Solve equation for y
- Thread starter sherwin01
- Start date
We could start with solving for z. You need to get z by itself obviously, so move 6/y to the other side:
2x - 6/y = 4z
Than divide both sides by 4:
1/4(2x - 6/y) = z
Simplify that to get your answer.
Now, the other is a little more difficult. I'll get you started though. You have y as the denominator in a fraction and you would like to to work with an equation without fractions. What you do to get rid of fractions in an equation is to multiply the equation(both sides) by the LCD. Which if you look at the equation there is only one fraction, so the LCD is y in this case.
In moving on from that step I would keep factoring in mind when getting y by itself.
2x - 6/y = 4z
Than divide both sides by 4:
1/4(2x - 6/y) = z
Simplify that to get your answer.
Now, the other is a little more difficult. I'll get you started though. You have y as the denominator in a fraction and you would like to to work with an equation without fractions. What you do to get rid of fractions in an equation is to multiply the equation(both sides) by the LCD. Which if you look at the equation there is only one fraction, so the LCD is y in this case.
In moving on from that step I would keep factoring in mind when getting y by itself.
skeeter
Elite Member
- Joined
- Dec 15, 2005
- Messages
- 3,215
to solve for y, start by reducing each term (notice that all terms have a common factor of 2) ...
2x - 6/y = 4z
x - 3/y = 2z
swap the positions of the 3/y term and the 2z term ...
x - 2z = 3/y
now for an algebra "shortcut" ... if a+b = c/d, then d = c/(a+b) {note that d and the quantity (a+b) swap positions) ... apply this principle to the above equation
y = 3/(x - 2z)
you're done.
2x - 6/y = 4z
x - 3/y = 2z
swap the positions of the 3/y term and the 2z term ...
x - 2z = 3/y
now for an algebra "shortcut" ... if a+b = c/d, then d = c/(a+b) {note that d and the quantity (a+b) swap positions) ... apply this principle to the above equation
y = 3/(x - 2z)
you're done.