Please help need it!!

[djdownfawl]

Please look at this i solved everything just cannot understand how to do number C
Please help me.
Thanks in advance

 

[galactus]

The slopes of the tangent lines are the slopes of f(x) at that point.

f(x)=1-x^2

f'(x)=-2x

Say, we have (-1,0)

f'(-1)=-2(-1)=2

Using y=mx+b:

0=2(-1)+b

b=2

The line has equation y=2x+2 at the point (-1,0).

Check the other two in a similar manner. They should match up.