Y yess New member Joined Sep 17, 2010 Messages 5 Sep 23, 2010 #1 algebraically simplify [f(x+deltax)-f(x)]/delta x to -1/[(x+delta x-3)(x-3)] for f(x) = (x-2)/(x-3)
D Deleted member 4993 Guest Sep 23, 2010 #2 yess said: algebraically simplify [f(x+deltax)-f(x)]/delta x to -1/[(x+delta x-3)(x-3)] for f(x) = (x-2)/(x-3) Click to expand... \(\displaystyle f(x) \ = \ \frac{x-2}{x-3} \ = \ 1 \ + \ \frac{1}{x-3}\) \(\displaystyle f(x + \Delta x) \ = \ 1 \ + \ \frac{1}{(x + \Delta x)-3}\) Now continue... Please show us your work, indicating exactly where you are stuck - so that we may know where to begin to help you
yess said: algebraically simplify [f(x+deltax)-f(x)]/delta x to -1/[(x+delta x-3)(x-3)] for f(x) = (x-2)/(x-3) Click to expand... \(\displaystyle f(x) \ = \ \frac{x-2}{x-3} \ = \ 1 \ + \ \frac{1}{x-3}\) \(\displaystyle f(x + \Delta x) \ = \ 1 \ + \ \frac{1}{(x + \Delta x)-3}\) Now continue... Please show us your work, indicating exactly where you are stuck - so that we may know where to begin to help you
