Pls help with this one

S

shy5577

New member
Joined
Nov 21, 2005
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6
f(x)=2x^3+3x^2-36x+2 defined on interval [-6,5]

I need to find rel max and min values and absolute max and min (if there's any)

Here's what I did:
Found first derivative 6x^2+6x-36

Then I found f(-6) = -106 and f(5) = 219

Is that right? where do I go from here?
thanks
 
Find where f'(x)=0! Say at x=a.
The compare f(a) with your two other values.
 
OK

I got f'(x)=0 at -1 and 6

I'm not sure what you mean by compare. Do you mean plug -1 and 6 back into the function?

By doing that, I got 39 and 326...
Are those my points for the graph
(-6,-106)
(-1,39)
(5,219)
(6,326)

Absolute min -106?
Absolute max 326?
 
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