Polygons

[learnerjack]

If m

CBD = 81°, m

CED = 60° and m

BCE = 75°, find the measure of

1 and

2.

I really have no idea where to start at all.

 

[winsome]

Solution:
First thing I notice in this problem: - there is a large triangle and a small triangle.

EAC,

ACE, and

CEA are three angles of larger triangle.
Means they have to add up to 180[sup:2a1e18cq]0[/sup:2a1e18cq]
m

1 + 75 + 60 = 180
m

1 + 135 = 180
m

1 = 45[sup:2a1e18cq]0[/sup:2a1e18cq]

DAB,

ABD, and

BDA are three angles of smaller triangle.
Before finding m

2, we have to find

ABD.

ABD and angle with the measure of 81[sup:2a1e18cq]0[/sup:2a1e18cq] are supplementary.
Thus m

ABD = 180 – 81 = 99[sup:2a1e18cq]0[/sup:2a1e18cq]

In smaller triangle

DAB +

ABD +

BDA = 180
45 + 99 + m

2 = 180
144 + m

2 = 180
m

2 = 36[sup:2a1e18cq]0[/sup:2a1e18cq]

Answer: m

1 = 45[sup:2a1e18cq]0[/sup:2a1e18cq] and m

2 = 36[sup:2a1e18cq]0[/sup:2a1e18cq]

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[Denis]

If m

CBD = 81°, m

CED = 60° and m

BCE = 75°, find the measure of

1 and

2.

I really have no idea where to start at all.

If you have "no idea", you need classroom help, PLUS start listening...

 

[mmm4444bot]

Denis, learnerjack is winsome posting fake requests for help so they can advertise.

The log-on credentials for winsome, learnerjack, Jhonson9009, Nelson01 should all be killed.