Population over time question

[jeffery_schlup]

Hi I believe I have answers to A and C. I do have an answer to Part B but I am unsure if it is correct:

(A) x(t)=ce^(t/2) where c is the initial population

(B) 2ln(e^-1/c)

(C) Popluation after 5 years = 8208

 

[Romsek]

You have a sign error in (A)

(B) is just incorrect.

\(\displaystyle \text{Solve $c e^{-\tau/2} =c e^{-1}$ for $\tau$}\)

(C) is correct so I guess the sign error in (A) was a typo.