An arrow is shot straight upward with a velocity of 98 feet per second (ft/sec) from an altitude of 8 feet. For how many seconds is this arrow more than 88 feet high? The altitude of the arrow is given by S = -16t2 + 98t + 8.
(Round your answer to two decimal places.)
This question was issued to me by my online math class, in a section covering interval notation and interval methods. I feel as if I would know how to solve it if it were asking for an interval. I tried using the quadratic formula to factor 88=-16t2+98t +8 or 0< 16t2+98t+8 and I got t is equal to .97 or 5.16 but neither of those worked so i tried using them as boundary points and that didnt work either. This online math class is terrible! I feel as if I am taking the wrong approach but mostly I feel lost...
(Round your answer to two decimal places.)
This question was issued to me by my online math class, in a section covering interval notation and interval methods. I feel as if I would know how to solve it if it were asking for an interval. I tried using the quadratic formula to factor 88=-16t2+98t +8 or 0< 16t2+98t+8 and I got t is equal to .97 or 5.16 but neither of those worked so i tried using them as boundary points and that didnt work either. This online math class is terrible! I feel as if I am taking the wrong approach but mostly I feel lost...