Prμ(i|E)=Prν(i|E) for all i ----> d(μ,v)<= max(Prμ(not(E)),Prν(not(E)))

barak

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Oct 28, 2020
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I have question that I couldn't solve by myself I hope you guys could assist:
there are two Probabilistic dimensions μ,v above 1,2,3..,n we know that ∀ Prμ(i|E)=Prν(i|E)
we need to prove that
d(μ,v)≤max(Prμ(not(E)),Prν(not(E)))
 
I have question that I couldn't solve by myself I hope you guys could assist:
there are two Probabilistic dimensions μ,v above 1,2,3..,n we know that ∀ Prμ(i|E)=Prν(i|E)
we need to prove that
d(μ,v)≤max(Prμ(not(E)),Prν(not(E)))
Please show us what you have tried and exactly where you are stuck.

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