cosx-5=3cosx+6
D Deleted member 4993 Guest Dec 4, 2011 #2 Check your post for accuracy - then show your work to get proper help...
V vbeierschmitt New member Joined Dec 4, 2011 Messages 2 Dec 5, 2011 #3 thats the problem from the book. Dont no how to get started solving
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,962 Dec 5, 2011 #4 vbeierschmitt said: cosx-5=3cosx+6 Click to expand... Your book should show grouping symbols around function inputs. If it does not, then we must assume that the angle (i.e., the input to each cosine function) is simply x. cos(x) - 5 = 3*cos(x) + 6 This equation has no Real solution. To see why, do the algebra: (1) Subtract cos(x) from both sides (2) Subtract 6 from both sides (3) Simplify You should arrive at: cos(x) = -11/2 This equation has no Real solution because -11/2 is smaller than -1 and the range of the cosine function is [1, -1]. If I wrote anything that you do not understand, please ask a specific question. Cheers! :cool:
vbeierschmitt said: cosx-5=3cosx+6 Click to expand... Your book should show grouping symbols around function inputs. If it does not, then we must assume that the angle (i.e., the input to each cosine function) is simply x. cos(x) - 5 = 3*cos(x) + 6 This equation has no Real solution. To see why, do the algebra: (1) Subtract cos(x) from both sides (2) Subtract 6 from both sides (3) Simplify You should arrive at: cos(x) = -11/2 This equation has no Real solution because -11/2 is smaller than -1 and the range of the cosine function is [1, -1]. If I wrote anything that you do not understand, please ask a specific question. Cheers! :cool: