precalc help

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cosx-5=3cosx+6

Your book should show grouping symbols around function inputs.

If it does not, then we must assume that the angle (i.e., the input to each cosine function) is simply x.

cos(x) - 5 = 3*cos(x) + 6

This equation has no Real solution.

To see why, do the algebra:

(1) Subtract cos(x) from both sides

(2) Subtract 6 from both sides

(3) Simplify

You should arrive at:

cos(x) = -11/2

This equation has no Real solution because -11/2 is smaller than -1 and the range of the cosine function is [1, -1].

If I wrote anything that you do not understand, please ask a specific question. Cheers! :cool:
 
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