J Janet Ward New member Joined Sep 6, 2010 Messages 8 Sep 6, 2010 #1 In factoring fractional exponents when factoring (2+x)^-2/3 x+(2+x)^1/3=(2+x)^-2/3[x+(2+x)] What happened to the 1/3 power?
In factoring fractional exponents when factoring (2+x)^-2/3 x+(2+x)^1/3=(2+x)^-2/3[x+(2+x)] What happened to the 1/3 power?
D Deleted member 4993 Guest Sep 6, 2010 #2 Janet Ward said: In factoring fractional exponents when factoring (2+x)^-2/3 x+(2+x)^1/3=(2+x)^-2/3[x+(2+x)] What happened to the 1/3 power? Click to expand... (2+x) * (2+x)[sup:w4zaqhw8]-2/3[/sup:w4zaqhw8] = (2 + x)[sup:w4zaqhw8](1 - 2/3)[/sup:w4zaqhw8] = (2+x)[sup:w4zaqhw8]1/3[/sup:w4zaqhw8]
Janet Ward said: In factoring fractional exponents when factoring (2+x)^-2/3 x+(2+x)^1/3=(2+x)^-2/3[x+(2+x)] What happened to the 1/3 power? Click to expand... (2+x) * (2+x)[sup:w4zaqhw8]-2/3[/sup:w4zaqhw8] = (2 + x)[sup:w4zaqhw8](1 - 2/3)[/sup:w4zaqhw8] = (2+x)[sup:w4zaqhw8]1/3[/sup:w4zaqhw8]
