precalculus

[Janet Ward]

In factoring fractional exponents when factoring (2+x)^-2/3 x+(2+x)^1/3=(2+x)^-2/3[x+(2+x)] What happened to the 1/3 power?

 

[Deleted member 4993]

In factoring fractional exponents when factoring (2+x)^-2/3 x+(2+x)^1/3=(2+x)^-2/3[x+(2+x)] What happened to the 1/3 power?

(2+x) * (2+x)[sup:w4zaqhw8]-2/3[/sup:w4zaqhw8] = (2 + x)[sup:w4zaqhw8](1 - 2/3)[/sup:w4zaqhw8] = (2+x)[sup:w4zaqhw8]1/3[/sup:w4zaqhw8]