Going through a practice paper I came across this question.
A building has 20 floors
4 floors have shops only
9 floors are offices only
7 floors are apartments only
3 floors are chosen at random for safety checks
what is the probability that:
a) All three floors have apartments
b) Two floors have shops and one floor has offices
c) The floors are of different types
My workings
for a) p = 7/20 x 6/19 x 5/18
for b) p = 4/20 x 3/19 x 9/18
for c) p = 4/20 x 9/19 x 7/18
Seems like a is right but the other two are wrong, just wondering why.
A building has 20 floors
4 floors have shops only
9 floors are offices only
7 floors are apartments only
3 floors are chosen at random for safety checks
what is the probability that:
a) All three floors have apartments
b) Two floors have shops and one floor has offices
c) The floors are of different types
My workings
for a) p = 7/20 x 6/19 x 5/18
for b) p = 4/20 x 3/19 x 9/18
for c) p = 4/20 x 9/19 x 7/18
Seems like a is right but the other two are wrong, just wondering why.