Probability with and without replacement

[Zelda22]

Am I calculating this right? Thank you.

a. Without replacement
Jack- EVE
p(J) = p(E) * p(V) * p(E)
= 2/3 * 1/2 * 1
= 1/3

b. Without remplacement
Richie- EVEEVE
p(R) = p(E) * p(V) * p(E)
= 2/3 * 2/5 * 3/4
= 1/5


c. With remplacement
Jack- EVE
p(J) = p(E) * p(V) * p(E)
= 2/3 * 1/3 * 2/3
= 4/27

d. With remplacement
Richie- EVEEVE
p(R) = p(E) * p(V) * p(E)
= 2/3 * 1/3 * 2/3
= 4/27

 

[blamocur]

Looks perfect to me.

 

[Zelda22]

thank you