M mcwang719 Junior Member Joined Mar 22, 2006 Messages 67 Apr 6, 2006 #1 hello. this seems like an easy integral i just can't seem to get the right solution which is y^2/4 int y^2/2y dy. can someone help. thanks!!
hello. this seems like an easy integral i just can't seem to get the right solution which is y^2/4 int y^2/2y dy. can someone help. thanks!!
S soroban Elite Member Joined Jan 28, 2005 Messages 5,584 Apr 6, 2006 #2 Hello, mcwang719! \(\displaystyle \int \frac{y^2}{2y}\,dy\) Answer: \(\displaystyle \frac{y^2}{4}\) Click to expand... Did you notice that: \(\displaystyle \,\frac{y^2}{2y}\;=\;\frac{y}{2}\;?\)
Hello, mcwang719! \(\displaystyle \int \frac{y^2}{2y}\,dy\) Answer: \(\displaystyle \frac{y^2}{4}\) Click to expand... Did you notice that: \(\displaystyle \,\frac{y^2}{2y}\;=\;\frac{y}{2}\;?\)
M mcwang719 Junior Member Joined Mar 22, 2006 Messages 67 Apr 6, 2006 #3 thanks soroban!! im so blind.
