Proof Check

vampirewitchreine

Junior Member
Joined
Aug 2, 2011
Messages
82
Okay, so this one was throwing me off for a bit, but I think that I might have this one down. If you would be ever so kind to check this and make sure that my reasonings are good, I would greatly appreciate it.

(Black are from the book, red is the information that I filled in)

8.jpg
Given: segment AE || segment DC, segment AB is congruent to segment DB
Prove: ▲ABE is congruent to ▲DCB

StatementReason
1. segment AE || segment DC, segment AB is congruent to segment DB1. Given
2. angle ABE is congruent to angle DBC2. Vertical angles are congruent
3. segment EB is congruent to segment BC3. Definition of midpoint
4. ▲ABE is congruent to ▲DBC4. SAS




Okay, so my reasonings for #1 and #2 are obvious.
I chose to use that segment EB was congruent to BC by the definition of midpoint in #3 as B would need to be the midpoint of AD to make both smaller segments (AB and DB) congruent to each other.
For #4, You have sides that are congruent to corresponding parts of the other triangle with an angle between the two sides that is also congruent to the corresponding part of another triangle.
 
Hello, vampirewitchreine!

If you would be ever so kind to check this, I would greatly appreciate it.

(Black are from the book, red is the information that I filled in)

View attachment 1561
Given: segment AE || segment DC, segment AB is congruent to segment DB
Prove: ▲ABE is congruent to ▲DCB

Statement
Reason
1. segment AE || segment DC, segment AB is congruent to segment DB
1. Given
2. angle ABE is congruent to angle DBC
2. Vertical angles are congruent
3. segment EB is congruent to segment BC
3. Definition of midpoint
4. ▲ABE is congruent to ▲DBC
4. SAS





Your statement 3 is very shaky.
B\displaystyle B is the midpoint of AD,\displaystyle AD,
. . but it is not obvious that B\displaystyle B is the midpoint of EC.\displaystyle EC.

You didn't use the fact that AEDC.\displaystyle AE \parallel DC.

You could have had:

3.A=D3.alt-int angles4.ΔABEΔDBC4.ASA\displaystyle \begin{array}{|cc|cc|} \hline 3. & \angle A = \angle D & 3. & \text{alt-int angles} \\ \hline 4. & \Delta ABE \cong \Delta DBC & 4. & ASA \\ \hline \end{array}
 
Okay, so this one was throwing me off for a bit, but I think that I might have this one down. If you would be ever so kind to check this and make sure that my reasonings are good, I would greatly appreciate it.

(Black are from the book, red is the information that I filled in)

View attachment 1561
Given: segment AE || segment DC, segment AB is congruent to segment DB
Prove: ▲ABE is congruent to ▲DCB

StatementReason
1. segment AE || segment DC, segment AB is congruent to segment DB1. Given
2. angle ABE is congruent to angle DBC2. Vertical angles are congruent
3. segment EB is congruent to segment BC3. Definition of midpoint
4. ▲ABE is congruent to ▲DBC4. SAS





Okay, so my reasonings for #1 and #2 are obvious.
I chose to use that segment EB was congruent to BC by the definition of midpoint in #3 as B would need to be the midpoint of AD to make both smaller segments (AB and DB) congruent to each other.
For #4, You have sides that are congruent to corresponding parts of the other triangle with an angle between the two sides that is also congruent to the corresponding part of another triangle.
Your #'s 3&4 are wrong.
It is not given that B is the midpoint of EC.
But you can use alternate interior angles to get ASA.
 
Hello, vampirewitchreine!


Your statement 3 is very shaky.
B\displaystyle B is the midpoint of AD,\displaystyle AD,
. . but it is not obvious that B\displaystyle B is the midpoint of EC.\displaystyle EC.

This was only an assumption that dawned on my as I stared blankly at the proof for 10 minutes

You didn't use the fact that AEDC.\displaystyle AE \parallel DC.

This was in statement one


You could have had:

3.A=D3.alt-int angles4.ΔABEΔDBC4.ASA\displaystyle \begin{array}{|cc|cc|} \hline 3. & \angle A = \angle D & 3. & \text{alt-int angles} \\ \hline 4. & \Delta ABE \cong \Delta DBC & 4. & ASA \\ \hline \end{array}

Thank you for the corrections (you too pka). Proof's are not my strong point, which is why I post them a lot.
 
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