Proof for the statement: "the equation ax+by+c=0 always expresses only 1 line"

Zach001

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Can I get the proof for the statement: "the equation ax+by+c=0 always expresses only 1 line"
 
Can I get the proof for the statement: "the equation ax+by+c=0 always expresses only 1 line"
This depends on what you consider "proof". I.e., what is the set of axioms and/or theorems which we can take for granted ?

Would it be enough to prove that any 3 points satisfying the equation lie on a straight line? In this case we can refer to Euclid's axioms, i.e., there is exactly one straight line for any pair of points.
 
Suppose that 1 & 2\ell_1~\&~\ell_2 are two lines represented by the general linear equation Ax+By+C=0Ax+By+C=0
Can you explain the following? From the given there must be a point (p,q)(p,q). on one of lines but not the other.
Say it is is on 1\ell_1. Because Ax+By+C=0Ax+By+C=0 determines 1\ell_1 we have Ap+Bq+C=0Ap+Bq+C=0, WHY?
Now can you explain why (p,q)2 means that Ap+Bq+C0 ?(p,q)\notin\ell_2\text{ means that }Ap+Bq+C\ne 0~?
Please reply with what you are able to do.




 
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