Proof of Differentiation Rules

Hint: Find the first derivative of [imath][p(x)]^2-[q(x)]^2[/imath]
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Do I add in some kind of expression that equals zero but that also allows me to rearrange and factor things even further now? Or, would the 2 lead me to the constant I'm looking for?
 
Substitute [imath]p'(x)[/imath] by [imath]q(x)[/imath] and [imath]q'(x)[/imath] by [imath]p(x)[/imath]. What can you conclude from the value of derivative?
 
Substitute [imath]p'(x)[/imath] by [imath]q(x)[/imath] and [imath]q'(x)[/imath] by [imath]p(x)[/imath]. What can you conclude from the value of derivative?
It equals zero? OH, so therefore there must be a constant!! But why must it equal a constant?
 
Take for granted: If [imath]f'(x)=0[/imath] on [imath](a,b)[/imath] then [imath]f(x)[/imath] must be constant.
 
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