\(\displaystyle \lim_{x\to 2}\frac{x^{2}+x-6}{x-2}=5\)
I eventually end up at this:
\(\displaystyle 0< |x-2|<\delta\) implies \(\displaystyle |x-2|<\epsilon\)
Once I reach this, I do not know if I need to prove it any further. Do I need to continue on to prove this or do I leave it as is?
Thanks in advanced
I eventually end up at this:
\(\displaystyle 0< |x-2|<\delta\) implies \(\displaystyle |x-2|<\epsilon\)
Once I reach this, I do not know if I need to prove it any further. Do I need to continue on to prove this or do I leave it as is?
Thanks in advanced