Prove a = v(dv/ds)

dagr8est

Junior Member
Joined
Nov 2, 2004
Messages
128
a = acceleration
v = velocity
t = time
s = displacement

a = dv/dt = d(ds/dt)/dt

Then I'm stuck. I know it has something to do with the chain rule but I can't see it. :( Any help will be appreciated.
 
a=dvdt\displaystyle a = \frac{dv}{dt}

av=(dvdt)(1v)\displaystyle \frac{a}{v} = (\frac{dv}{dt}) (\frac{1}{v})

av=(dvdt)(dtds)\displaystyle \frac{a}{v} = (\frac{dv}{dt}) (\frac{dt}{ds})

av=dvds\displaystyle \frac{a}{v} = \frac{dv}{ds}

a=v(dvds)\displaystyle a = v (\frac{dv}{ds})
 
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