lancer6238
New member
- Joined
- Apr 4, 2007
- Messages
- 3
Hi all, I need help proving an inequality.
Suppose the function f(t,x) is locally Lipschitz on the domain G⊂R2, that is, ∣f(t,x1)−f(t,x2)∣≤k(t)∣x1−x2∣ for all (t,x1),(t,x2)∈G. Define I = (a,b) and ϕ1(t) and ϕ2(t) are 2 continuous functions on I. Assume that, if (t,ϕi(t))∈G, then the function f(t,ϕi(t)) is an integrable function on I for i = 1, 2. Suppose that for i = 1,2 and t∈I,
ϕi(t)=ϕi(t0)+∫t0tf(s,ϕi(s))ds+Ei(t)
and ∣ϕ1(t0)−ϕ2(t0)∣≤δ
for some constant δ. Show that for all t∈(t0,b) we have
∣ϕ1(t)−ϕ2(t)∣≤δe∫t0tk(s)ds+E(t)+∫t0tE(s)k(s)e∫t0sk(r)drds
where E(t)=∣E1(t)∣+∣E2(t)∣
I managed to get δe∫t0tk(s)ds using triangle inequality and Gronwall's inequality, but I cannot seem to get the last 2 terms in the inequality.
Here's what I did:
∣ϕ1(t)−ϕ2(t)∣
=∣ϕ1(t0)+∫t0tf(s,ϕ1(s))ds+E1(t)−ϕ2(t0)−∫t0tf(s,ϕ2(s))ds−E2(t)∣
=∣ϕ1(t0)−ϕ2(t0)+∫t0tf(s,ϕ1(s))ds−∫t0tf(s,ϕ2(s))ds+E1(t)−E2(t)∣
\(\displaystyle \leq |\phi_1(t_0) - \phi_2(t_0)| + |\int^t_{t_0} f(s, \phi_1(s)) }ds - \int^t_{t_0} f(s, phi_2(s)) \,ds + E_1(t) - E_2(t)|\)
≤δ+∣E1(t)−E2(t)∣+∣∫t0tf(s,ϕ1(s))−f(s,ϕ2(s))ds∣
≤δ+∣E1(t)+E2(t)∣+∫t0t∣f(s,ϕ1(s))−f(s,ϕ2(s))∣ds
≤δ+∣E1(t)∣+∣E2(t)∣+∫t0tk(s)∣ϕ1(s)−ϕ2(s)∣ds
≤(δ+E(t))e∫t0tk(s)ds
\(\displaystyle = \delta e^{\int^t_{t_0} k(s) \, ds} + E(t) e^{\int^t_{t_0} k(s) \, ds\)
This is where I got stuck.
Please help.
Thank you.
Regards,
Rayne
Suppose the function f(t,x) is locally Lipschitz on the domain G⊂R2, that is, ∣f(t,x1)−f(t,x2)∣≤k(t)∣x1−x2∣ for all (t,x1),(t,x2)∈G. Define I = (a,b) and ϕ1(t) and ϕ2(t) are 2 continuous functions on I. Assume that, if (t,ϕi(t))∈G, then the function f(t,ϕi(t)) is an integrable function on I for i = 1, 2. Suppose that for i = 1,2 and t∈I,
ϕi(t)=ϕi(t0)+∫t0tf(s,ϕi(s))ds+Ei(t)
and ∣ϕ1(t0)−ϕ2(t0)∣≤δ
for some constant δ. Show that for all t∈(t0,b) we have
∣ϕ1(t)−ϕ2(t)∣≤δe∫t0tk(s)ds+E(t)+∫t0tE(s)k(s)e∫t0sk(r)drds
where E(t)=∣E1(t)∣+∣E2(t)∣
I managed to get δe∫t0tk(s)ds using triangle inequality and Gronwall's inequality, but I cannot seem to get the last 2 terms in the inequality.
Here's what I did:
∣ϕ1(t)−ϕ2(t)∣
=∣ϕ1(t0)+∫t0tf(s,ϕ1(s))ds+E1(t)−ϕ2(t0)−∫t0tf(s,ϕ2(s))ds−E2(t)∣
=∣ϕ1(t0)−ϕ2(t0)+∫t0tf(s,ϕ1(s))ds−∫t0tf(s,ϕ2(s))ds+E1(t)−E2(t)∣
\(\displaystyle \leq |\phi_1(t_0) - \phi_2(t_0)| + |\int^t_{t_0} f(s, \phi_1(s)) }ds - \int^t_{t_0} f(s, phi_2(s)) \,ds + E_1(t) - E_2(t)|\)
≤δ+∣E1(t)−E2(t)∣+∣∫t0tf(s,ϕ1(s))−f(s,ϕ2(s))ds∣
≤δ+∣E1(t)+E2(t)∣+∫t0t∣f(s,ϕ1(s))−f(s,ϕ2(s))∣ds
≤δ+∣E1(t)∣+∣E2(t)∣+∫t0tk(s)∣ϕ1(s)−ϕ2(s)∣ds
≤(δ+E(t))e∫t0tk(s)ds
\(\displaystyle = \delta e^{\int^t_{t_0} k(s) \, ds} + E(t) e^{\int^t_{t_0} k(s) \, ds\)
This is where I got stuck.
Please help.
Thank you.
Regards,
Rayne