quad formula

[airplanes123]

problem: 3x^2 +9x-5=0
after simplfying i have x= -9 +/- sqrt 141 all divided by 6.
where do i go from here? can i go any further....

 

[mmm4444bot]

3x^2 + 9x - 5 = 0

x = [-9 +/- sqrt(141)]/6

Your result is accurate.

It can also be written as follows by decomposing your ratio into two fractions and canceling common factors, but your form and the following form both represent the same answer.

$\displaystyle x \;=\; -\frac{3}{2} \pm \frac{\sqrt{141}}{6}$