Quadratic equation help

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otavukcuoglu

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Hi everyone;

Can someone explain this question with details. Thank you
 

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Subhotosh Khan said:
What are your thoughts?

Please share your work with us ...even if you know it is wrong.

If you are stuck at the beginning tell us and we'll start with the definitions.

You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL:

http://www.freemathhelp.com/forum/announcement.php?f=33
Click to expand...


Sorry about that.

I tried sum up roots first then put the values from first equation by using -b/a then i tried to multiply the roots the write the values which come from first equation but i confused about 3x^2 I've never seen that before.
 
otavukcuoglu said:
attachment.php


Hi everyone;

Can someone explain this question with details. Thank you
Click to expand...

You need to solve for α and ß from the equation 3x2 + 2x - 3 = 0 ( ← Ax2 + Bx + C = 0)

so α + ß = - B/A = -2/3

α*ß = C/A = -1

Then

(α - ß)2 = (α + ß)2 - 4α*ß → α - ß = ? → α = ? & ß = ?
 
Subhotosh Khan said:
You need to solve for α and ß from the equation 3x2 + 2x - 3 = 0 ( ← Ax2 + Bx + C = 0)

so α + ß = - B/A = -2/3

α*ß = C/A = -1

Then

(α - ß)2 = (α + ß)2 - 4α*ß → α - ß = ? → α = ? & ß = ?
Click to expand...


I didn't get the last part sorry. Do I have to find the roots ? I thought I needed to factorise the question to make it in (α + ß) and (αß) form ?
 
otavukcuoglu said:
I didn't get the last part sorry. Do I have to find the roots ? I thought I needed to factorise the question to make it in (α + ß) and (αß) form ?
Click to expand...

You can do that!

However, you were confused by the coefficient of x2 term (3) - that's why I showed you an alternate way.
 
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