mathdad
Full Member
- Joined
- Apr 24, 2015
- Messages
- 737
Solve the inequality.
x^2 - x - 6 > 0
Replace > with the = symbol.
x^2 - x - 6 = 0
Factor.
(x - 3)(x + 2) = 0
Solve each factor for x.
x = 3 and x = - 2
Pick a number between
-2 & 3.
Let x = 0
x^2 - x - 6 > 0
(0)^2 - 0 - 6 > 0
- 6 > 0...false statement.
I understand this to mean that the given function DOES NOT have a solution on the interval
(-2, 3).
I conclude from this finding that x^2 - x - 6 is greater than 0 in the intervals
(-infinity, -2) and (3, infinity).
Note:
Do I say (-infinity, -2) and (3, infinity)?
Should I say (-infinity, - 2) or (3, infinity)?
x^2 - x - 6 > 0
Replace > with the = symbol.
x^2 - x - 6 = 0
Factor.
(x - 3)(x + 2) = 0
Solve each factor for x.
x = 3 and x = - 2
Pick a number between
-2 & 3.
Let x = 0
x^2 - x - 6 > 0
(0)^2 - 0 - 6 > 0
- 6 > 0...false statement.
I understand this to mean that the given function DOES NOT have a solution on the interval
(-2, 3).
I conclude from this finding that x^2 - x - 6 is greater than 0 in the intervals
(-infinity, -2) and (3, infinity).
Note:
Do I say (-infinity, -2) and (3, infinity)?
Should I say (-infinity, - 2) or (3, infinity)?