can u please help me to find out the roots of x^2+8x+12 = 0 thank u
S Stefan New member Joined Jun 30, 2013 Messages 1 Jun 30, 2013 #1 can u please help me to find out the roots of x^2+8x+12 = 0 thank u
S serds Junior Member Joined May 30, 2013 Messages 55 Jun 30, 2013 #2 That's a quadratic equation with 0 = Solve it with the quadratic formula x1/2 = or you can use the pq-formula: with: X1/2 = Last edited: Jun 30, 2013
That's a quadratic equation with 0 = Solve it with the quadratic formula x1/2 = or you can use the pq-formula: with: X1/2 =
H HallsofIvy Elite Member Joined Jan 27, 2012 Messages 7,763 Jun 30, 2013 #3 Stefan said: can u please help me to find out the roots of x^2+8x+12 = 0 thank u Click to expand... That's easily factored: 2*6= 12 and 2+ 6= 8. \(\displaystyle x^2+ 8x+ 12= (x+ 2)(x+ 6)= 0\). You can also complete the square. Since 12= 16- 4 and \(\displaystyle (x+ 4)^2= x^2+ 8x+ 16\) \(\displaystyle x^2+ 8x+ 12= x^2+ 8x+ 16- 4= (x+ 4)^2- 4= 0\) \(\displaystyle (x+ 4)^2= 4\) Now take the square root of both sides.
Stefan said: can u please help me to find out the roots of x^2+8x+12 = 0 thank u Click to expand... That's easily factored: 2*6= 12 and 2+ 6= 8. \(\displaystyle x^2+ 8x+ 12= (x+ 2)(x+ 6)= 0\). You can also complete the square. Since 12= 16- 4 and \(\displaystyle (x+ 4)^2= x^2+ 8x+ 16\) \(\displaystyle x^2+ 8x+ 12= x^2+ 8x+ 16- 4= (x+ 4)^2- 4= 0\) \(\displaystyle (x+ 4)^2= 4\) Now take the square root of both sides.