Question

swag312

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Jan 9, 2020
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29
The marginal revenue function at output x is
MR (x) = 2x + 3.
Calculate revenue from the sale of 100 products.

Can't find a way to complete this task, is it somehow connected with derivatives?
 
How do you go from MR to R? Do you know how to go from R to MR? If you do, then just to the reverse.
 
Last edited:
Are you saying that this task is impossible to be completed?
What makes you think that?
In order for you to be able to do this problem you need to know the answer to either my 1st or 2nd question.

What do you do to R to get MR?
What do you do to MR to get R?
 
I don't know. I can't find this neither in my studying material or online lol.
 
I don't know. I can't find this neither in my studying material or online lol.
You really should know that the derivative of R is denoted by MR! Now you are given MR, so what is R going to be?
 
Oh yeah my bad, I misunderstood it. But where does the random number at the end come from? I understand the R = x2+3x part, but what about the following number?
 
so do I just put 100 instead of x and that's the answer ? i'm not digging it :/
 
R = pq, and I only have the value of q which is = 100. How do I get the answer in this case?
 
I would use a definite integral here:

The revenue from selling the first \(n\) items is:

[MATH]R(n)=\int_0^n MR(x)\,dx=\int_0^n 2x+3\,dx[/MATH]
Can you proceed?
 
Sorry for spam, but I am gessing that the answer is R = 10300, please correct me if I'm wrong.
 
Continuing my post above;

[MATH]R(n)=n^2+3n[/MATH]
And so:

[MATH]R(100)=100^2+3\cdot100=10300\quad\checkmark[/MATH]
 
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