Quick Question

[taylorg12345]

Is -12/13-5/13i the rectangular form of -2-3i/3+2i

 

[Romsek]

multiply top and bottom by the conjugate of the denominator and see what you get

 

[Steven G]

Did you mean to write -2-3i/3+2i? You do realize that -2-3i/3+2i = -2-i+2i=-2+1?

 

[taylorg12345]

Ok, I just didn't understand how to get -2-3i/3+2i into rectangular form.

 

[Dr.Peterson]

Is -12/13-5/13i the rectangular form of -2-3i/3+2i

Presumably you really mean (-2-3i)/(3+2i). Do you see why the parentheses are needed in order to mean `(-2-3i)/(3+2i)`?

Ok, I just didn't understand how to get -2-3i/3+2i into rectangular form.

It appears that the answer you gave is not your own, but the answer you were given. Is that right?

To put it into rectangular form, multiply the numerator and denominator by the conjugate of the latter, 3-2i. In doing so, watch your signs! Please show your work so we can point out the error(s), if any.

 

[pka]

Is -12/13-5/13i the rectangular form of -2-3i/3+2i

One of the most useful complex number formula to know is this:
if \(\large z=a+bi\) then \(\large \dfrac{1}{z}=\dfrac{\overline{~z~}}{|z|^2}=\dfrac{a-bi}{a^2+b^2}\)