S Sophiesmark New member Joined Nov 4, 2005 Messages 32 Nov 30, 2005 #1 Do I use the quotient rule for this one? And what is it cuz I dont see one in my text. Calculate the derivative of (sin(x)/cos(x))
Do I use the quotient rule for this one? And what is it cuz I dont see one in my text. Calculate the derivative of (sin(x)/cos(x))
U Unco Senior Member Joined Jul 21, 2005 Messages 1,134 Nov 30, 2005 #2 \(\displaystyle \Large \frac{\, \sin{x} \, }{ \, \cos{x} \, } = \tan{x}\)
R racuna New member Joined Sep 28, 2005 Messages 41 Nov 30, 2005 #3 (sin(x)/cos(x)) Again, treat it as two functions: f(x)/g(x), where f(x)=sinx and g(x)=cosx Quotient Rule tells us: g(x)*f'(x)-f(x)*g'(x)/(g(x)^2) Try it and see what you get.
(sin(x)/cos(x)) Again, treat it as two functions: f(x)/g(x), where f(x)=sinx and g(x)=cosx Quotient Rule tells us: g(x)*f'(x)-f(x)*g'(x)/(g(x)^2) Try it and see what you get.
R racuna New member Joined Sep 28, 2005 Messages 41 Nov 30, 2005 #4 you can also try what Unco said and just take the derivative of tanx
R racuna New member Joined Sep 28, 2005 Messages 41 Nov 30, 2005 #6 close! Remember to square the bottom: 1/(cosx)^2